AVAudioPlayer no longer working in Swift 2.0 / Xcode 7 beta

Question

For the var testAudio declaration in my iPhone app, I am receiving an error here

"Call can throw, but errors cannot be thrown out of a property initializer"

import UIKit
import AVFoundation
class ViewController: UIViewController {
    var testAudio = AVAudioPlayer(contentsOfURL: NSURL (fileURLWithPath: NSBundle.mainBundle().pathForResource("testAudio", ofType: "wav")!), fileTypeHint:nil)

This happened when I moved to the Xcode 7 beta.

How can I get this audio clip functioning in Swift 2.0?

Answer 1

Swift 2 has a brand new error handling system, you can read more about it here: Swift 2 Error Handling.

In your case, the AVAudioPlayer constructor can throw an error. Swift won't let you use methods that throw errors in property initializers because there is no way to handle them there. Instead, don't initialize the property until the init of the view controller.

var testAudio:AVAudioPlayer;

init() {
    do {
        try testAudio = AVAudioPlayer(contentsOfURL: NSURL (fileURLWithPath: NSBundle.mainBundle().pathForResource("testAudio", ofType: "wav")!), fileTypeHint:nil)
    } catch {
        //Handle the error
    }
}

This gives you a chance to handle any errors that may come up when creating the audio player and will stop Xcode giving you warnings.

Answer 2

Works for me in Swift 2.2

But don't forget to add the fileName.mp3 to the project Build phases->Copy Bundle Resources (right click on the project root)

var player = AVAudioPlayer()

func music()
{

    let url:NSURL = NSBundle.mainBundle().URLForResource("fileName", withExtension: "mp3")!

    do
    {
        player = try AVAudioPlayer(contentsOfURL: url, fileTypeHint: nil)
    }
    catch let error as NSError { print(error.description) }

    player.numberOfLoops = 1
    player.prepareToPlay()
    player.play()

}

Answer 3

If you know an error won't be returned you can add try! beforehand:

testAudio = try! AVAudioPlayer(contentsOfURL: NSURL (fileURLWithPath: NSBundle.mainBundle().pathForResource