I want to run this script:
#!/bin/bash
echo <(true)
I run it as:
sh file.sh
And I get "Syntax error: "(" unexpected" . I found some similar situations but still can't solve this.
I'm a beginner at shell scripting , but as I understand:
- the shebang I use is correct and chooses the bash shell , so the process substitution syntax should work
- I try the same from the command line and it works. I checked with
echo $0and it gives me "bash" , so what's the difference from running the command in the command line and from a script that invokes the same shell?
Maybe it's something simple, but I couldn't find an explanation or solution.
You should run your script with
bash, i.e. eitherbash ./script.shor making use of the shebang by./script.shafter setting it to executable. Only running it withsh ./script.shdo I get your error, as commented by Cyrus.See also: role of shebang at unix.SE