Batch file does not follow through with launching program once given permission by the user account control

Question

I have the following batch file:

for /f "delims=" %%x in (path.txt) do set path=%%x
set address=62.75.218.30:14567
start bf1942.exe

With path.txt file containing the path to the executable. Once I run the batch file I am prompted if I want to allow BF1942.exe to make changes to this computer (user account control). Once I select 'yes' nothing happens. Similarly when I launch BF1942.exe by double clicking on the icon I get the same prompt but the game launches after I give permission.

Edit: I did some investigation. When I moved the path.txt and the batch file into my Bf1942 folder and ran the batch file this worked. So the problem has something to do where the file is located.

Answer 1

Change the working directory (do not change the system environment variable path) as follows:

for /f "delims=" %%x in (path.txt) do set "myPath=%%~x"
set "address=62.75.218.30:14567"
pushd "%myPath%"
start "" bf1942.exe

or

set "address=62.75.218.30:14567"
for /f "delims=" %%x in (path.txt) do (
    pushd "%%~x"
    start "" bf1942.exe
)

Resources (required reading):

• (command reference) An A-Z Index of the Windows CMD command line
• (additional particularities) Windows CMD Shell Command Line Syntax
• (%~x etc. special page) Command Line arguments (Parameters)

Answer 2

You can either move your batch file to the same folder as the executable or specify the full path to the executable in the batch file.

For example:

start c:\Bf1942\bf1942.exe

Also, you shouldn't use path as a variable name. There is a system environment variable named path and your batch is overwriting it. Change yours to myPath or something else.