Batch Getting & Displaying User Input

Question

Why is this code not working?

@echo off
set /p param=Enter Parameters: 
echo %param%

Output:

(Nothing)

I have searched all relative posts, but I can't find what is wrong with it. There is no space problem, or syntax problem that I can identify

Update: As rojo stated, since the code block is working, here is the full code, which is not working.

@echo off

for /f %%j in ("java.exe") do (
    set JAVA_HOME=%%~dp$PATH:j
)

if %JAVA_HOME%.==. (
    echo java.exe not found
) else (
    set /p param=Enter Parameters: 
    echo %param%
    (statement using JAVA_HOME)
)

pause

Output:

Enter Parameters: jfdklsaj
ECHO is off.
...

Answer 1

As Laf indicated, this can be fixed with delayed expansion:

@echo off
setlocal enableDelayedExpansion

for /f %%j in ("java.exe") do (
set JAVA_HOME=%%~dp$PATH:j
)

if %JAVA_HOME%.==. (
    echo java.exe not found
) else (
    set /p param=Enter Parameters: 
    echo !param!
    (statement using JAVA_HOME)
)