Build dict from list of pairs that is made from string

Question

Say we have a string like

s = "a=b&c=d&xyz=abc"

I would like to get dictionary

{"a": "b", "c": "d", "xyz": "abc"}

This is one way how to achieve this:

dict([item.split("=") for item in s.split("&")])

This using generator is a bit better

dict(item.split("=") for item in s.split("&"))

Is there some more elegant way? I tried this to take advantage of new walrus operator but it does not looks any better:

{(pair := item.split("="))[0]: pair[1] for item in s.split("&")}

EDIT: I am looking for something single pass, without creating temporary list, or even one or more temporary tuples per item. Just building the dict directly... Would there be something along these lines?

Answer 1

From your example,

d = {u.split('=')[0]:u.split('=')[1] for u in s.split('&')}.

Answer 2

try this:

s = "a=b&c=d&xyz=abc"

lst = [z for y in s.split("&") for z in y.split("=")]
    
dct = {lst[i]: lst[i+1] for i in range(0, len(lst), 2)}

dct

output:

{'a': 'b', 'c': 'd', 'xyz': 'abc'}