Today I wanted to try sth new in image processing in C#.
Szenario as following: I have two black and white images. Now I want to get all white pixels (x,y) from both images and put them into a return image. So in the end my image3 contains all white pixels from image1 and image2. I'm using unsafe pointers as they are faster.
So in the code I check if image1 in (x,y) == image2 in (x,y) as it is very unlikely that both pictures have a white pixel at the same spot
My approach right now:
private unsafe static Bitmap combine_img(Bitmap img1, Bitmap img2)
{
Bitmap retBitmap = img1;
int width = img1.Width;
int height = img1.Height;
BitmapData image1 = retBitmap.LockBits(new Rectangle(0, 0, width, height), ImageLockMode.ReadWrite, PixelFormat.Format24bppRgb);
BitmapData image2 = img2.LockBits(new Rectangle(0, 0, width, height), ImageLockMode.ReadWrite, PixelFormat.Format24bppRgb); // here an error
byte* scan1 = (byte*)image1.Scan0.ToPointer();
int stride1 = image1.Stride;
byte* scan2 = (byte*)image2.Scan0.ToPointer();
int stride2 = image2.Stride;
for (int y = 0; y < height; y++)
{
byte* row1 = scan1 + (y * stride1);
byte* row2 = scan2 + (y * stride2);
for (int x = 0; x < width; x++)
{
if (row1[x] == row2[x])
row1[x] = 255;
}
}
img1.UnlockBits(image1);
img2.UnlockBits(image2);
return retBitmap;
}
unfortunately it returns an error when trying to lock the second image, saying the image has already been locked!
The problem was, that strangely I did pass the same image, here the corrected Code: