In my program, set
has elements of type pair<char, double>
. I also implemented the logic so that set
is sorted based on element's 2nd value, from smallest to largest:
using pair_item = std::pair<char, double>;
std::set<pair_item, decltype([](auto e1, auto e2){return e1.second < e2.second;})> pq;
Now, I want to delete an element from set
, based on element's 1st value:
auto first_is_w = std::lower_bound(
pq.begin(), pq.end(), [w](const auto& p) {
return p.first == w;
}
);
if (first_is_w != pq.end() && first_is_w->first == w) {
pq.erase(first_is_w);
}
Unfortunately, I got error:
'const A_star(const std::vector<std::tuple<char, char, double> >&, std::unordered_map<char, double>&, char, char)::<lambda(const auto:13&)>' is not derived from 'const std::optional<_Tp>'
{ return *__it < __val; }
~~~~~~^~~~~~~
I'm wondering how should I modify my lambda function to run the search correctly? Full codes attached below:
#include <iostream>
#include <set>
#include <utility>
using pair_item = std::pair<char, double>;
void printSet(const auto& pq) {
std::cout << "Current pq:" << std::endl;
for (const auto& ele : pq) {
std::cout << "(" << ele.first << ", " << ele.second << "), ";
}
std::cout << std::endl;
}
int main() {
char w = 'A';
std::set<pair_item, decltype([](auto e1, auto e2){return e1.second < e2.second;})> pq;
pq.emplace('A', 30);
pq.emplace('B', 20);
pq.emplace('C', 10);
printSet(pq);
auto first_is_w = std::lower_bound(
pq.begin(), pq.end(), [w](const auto& p) {
return p.first == w;
}
);
if (first_is_w != pq.end() && first_is_w->first == w) {
pq.erase(first_is_w);
}
return 0;
}
Your lambda is fine, but you're using the wrong algorithm.
lower_bound
requires a sorted range and strict weak ordering comparison, which you do not have for the value you're looking for.You should use
std::find_if
, which is an O(N) linear search.