cakephp-2.0 simplest ajax link with jshelper

Question

I want to create the most basic ajax link there is in Cakephp 2.0.

In index.ctp i have

 <?php
echo $this->Js->link('myLink', array('controller'=>'technologies', 'action'=>'view'), array('update'=>'#success'));
?>
 <div id="success"></div>

in TechnologiesController.php i have

public function view(){
    $this->set('msg', 'message');
    $this->render('view', 'ajax'); 
}

and in view.ctp i have

<?php echo $msg;?>

Instead of setting the view in the success div, it navigates to the http://local.cake.com/technologies/view page to display the message.

Any help much appreciated!

Answer 1

By default scripts are cached, and you must explicitly print out the cache. To do this at the end of each page, include this line just before the ending tag:

echo $this->Js->writeBuffer(); // Write cached scripts

I am using this at the end of my default.ctp in the Layouts Folder

Answer 2

I just put this:

echo $this->Js->writeBuffer();

it work for me, hope i will for you

Answer 3

try $this->autoRender = FALSE;

Answer 4

Be sure to set $components = array('RequestHandler') in your controller

Answer 5

I think you might have to put this:

echo $this->Js->writeBuffer();

somewhere - for example right below the $this->Js->link call.

Hope that helps!

Answer 6

So, in total the code would look like this - and it works for me (CakePHP 2.2.4):

index.ctp:

<?php
echo $this->Js->link('myLink', array('controller'=>'technologies', 'action'=>'view'), array('update'=>'#success'));
?>

<div id="success"></div>

echo $this->Js->writeBuffer();

Thank you a lot, this helped me understand how things work in 2.0 and above :)