cannot convert ‘char*’ to ‘int*’ for argument ‘1’ to ‘int median(int*, int)’ array2 = median(array,size);

Question

My problem is as I specify in the title: test_median.cpp:

In function ‘int main()’: test_median.cpp:26:27: error: cannot convert ‘char*’ to ‘int*’ for argument ‘1’ to ‘int median(int*, int)’

array2 = median(array,size);

So here is my code. This is the tester code;

#include <iostream>
#include <cmath>
#include "IpFunctions.h"

using namespace std;

int main()
{

int size;
cout<< "size gir" <<endl;
cin >> size;

int i;
char array[size];

cout<< "değerleri gir"<<endl;

for (i=0;i<size;i=i+1)
{
cin >> array[i];
}

char array2[size];

array2 = median(array,size);

cout<<"array2 = "<<array2<<endl;

return 0;
}

This is the median function code:

#include <iostream>
#include <cmath>

using namespace std;

int median(char array[], int size)
{
int i = 0;
int m,n;
while (i<size)
{
    if (array[i]>array[i+1])
    {
    m = array[i]; n = array[i+1];
    array[i] = n; array[i+1] = m;
    i=i+1;
    }
    else
    {
    i=i+1;
    }
}

return *array;

}

And finally "IpFunctions.h" header:

// this is just a headerfile that you add your Image processing functions' prototypes.
// when testing your functions with a main function
// main needs a prototype of the function

//Image medianfiltering(Image &inimg, const int size );
int median(int array[],int size);

// when you type a function add the header here !!! 
// such as 
// Image negative(Image &inimg);

So I just wanted to make a function to take the median of an array and return that array.

Answer 1

in the header

int median(int array[],int size);

in the .cpp file

int median(char array[], int size)

your main is trying to invoke the first one (its the only one it knows about)