In objective-C I was able to use:
CGSize stringsize =
[strLocalTelefone sizeWithAttributes:@{NSFontAttributeName:[UIFont systemFontOfSize:14.0f]}];
But in Swift Language I didn't found any solution for this situation.
Any Help?
Just use explicit casting:
var stringsize = (strLocalTelefone as NSString).sizeWithAtt...
Otherwise you can bridge it too:
Bridging is no longer supported in later versions of Swift.
var strLocalTelefone = "some string"
var stringsize = strLocalTelefone.bridgeToObjectiveC().sizeWithAttributes([NSFontAttributeName:UIFont.systemFontOfSize(14.0)])
This answer is worth at least looking at, as it highlights potential differences between the two approaches.
what I did is something like this:
let myString = "Some text is just here..."
let size: CGSize = myString.size(withAttributes: [.font: UIFont.systemFont(ofSize: 14)])
let myString = "Some text is just here..."
let size: CGSize = myString.size(withAttributes: [NSAttributedStringKey.font: UIFont.systemFont(ofSize: 14)])
var originalString: String = "Some text is just here..."
let myString: NSString = originalString as NSString
let size: CGSize = myString.size(attributes: [NSFontAttributeName: UIFont.systemFont(ofSize: 14.0)])
var originalString: String = "Some text is just here..."
let myString: NSString = originalString as NSString
let size: CGSize = myString.sizeWithAttributes([NSFontAttributeName: UIFont.systemFontOfSize(14.0)])
You can also use this piece of code, it's easier and you don't have to create new variable just to get NSString object:
var stringToCalculateSize:String = "My text"
var stringSize:CGSize = (stringToCalculateSize as NSString).sizeWithAttributes([NSFontAttributeName: UIFont.systemFontOfSize(14.0)])
Just one line solution:
yourLabel.intrinsicContentSize.width
for Objective-C / SwiftThis will work even your label text have custom text spacing.