Change subprocess.run architecture from x86 to arm

Question

I am running python on a m1 Mac with Rosetta, on a x86_64 architecture.

During the execution I need to use subprocess.run to launch some external program. However that program need to run under arm64 architecture.

Is there a possible solution for doing that? Simply running from an arm64 terminal does not do the trick, and it gets overridden by the Python architecture.

I am using python==3.8.2.

Answer 1

The root of the problem was actually not in the subprocess.run, the process I was trying to spawn was compiled such that the binary is multi-arch support, supporting both arm64 and x86_64 (the support for the latter was mainly launching the program and crashing after not supported error).

As the call for subprocess.run came from a x86_64 architecture, the binary defaulted to that architecture.

The solution was to just compile the binary only for arm64, with no multi-arch support. After that the process was spawned with the correct architecture, even tho the call was made from a different architecture.