Check if array contains part of a string in Swift?

Question

I have an array containing a number of strings. I have used contains() (see below) to check if a certain string exists in the array however I would like to check if part of a string is in the array?

itemsArray = ["Google, Goodbye, Go, Hello"]

searchToSearch = "go"

if contains(itemsArray, stringToSearch) {
    NSLog("Term Exists")
}
else {
    NSLog("Can't find term")
}

The above code simply checks if a value is present within the array in its entirety however I would like to find "Google, Google and Go"

Answer 1

Try like this.

let itemsArray = ["Google", "Goodbye", "Go", "Hello"]
let searchToSearch = "go"

let filteredStrings = itemsArray.filter({(item: String) -> Bool in

     var stringMatch = item.lowercaseString.rangeOfString(searchToSearch.lowercaseString)
     return stringMatch != nil ? true : false
})

filteredStrings will contain the list of strings having matched sub strings.

In Swift Array struct provides filter method, which will filter a provided array based on filtering text criteria.

Answer 2

First of all, you have defined an array with a single string. What you probably want is

let itemsArray = ["Google", "Goodbye", "Go", "Hello"]

Then you can use contains(array, predicate) and rangeOfString() – optionally with .CaseInsensitiveSearch – to check each string in the array if it contains the search string:

let itemExists = contains(itemsArray) {
    $0.rangeOfString(searchToSearch, options: .CaseInsensitiveSearch) !=  nil
}

println(itemExists) // true 

Or, if you want an array with the matching items instead of a yes/no result:

let matchingTerms = filter(itemsArray) {
    $0.rangeOfString(searchToSearch, options: .CaseInsensitiveSearch) !=  nil
}

println(matchingTerms) // [Google, Goodbye, Go]

Update for Swift 3:

let itemExists = itemsArray.contains(where: {
    $0.range(of: searchToSearch, options: .caseInsensitive) != nil
})
print(itemExists)

let matchingTerms = itemsArray.filter({
    $0.range(of: searchToSearch, options: .caseInsensitive) != nil
})
print(matchingTerms)

Answer 3

I had the same problem recently, didn't like most of these answers, solved it like this:

let keywords = ["doctor", "hospital"] //your array

func keywordsContain(text: String) -> Bool { // text: your search text
    return keywords.contains { (key) -> Bool in
        key.lowercased().contains(text.lowercased())
    }
}

This will also correctly trigger searches like "doc", which many of the above answers do not and is best practice. contains() is more performant than first() != nil source: https://www.avanderlee.com/swift/performance-collections/

Answer 4

In Swift 5 with better readability :

let itemsArray = ["Google", "Goodbye", "Go", "Hello"]
let searchString = "Googled"

let result = itemsArray.contains(where: searchString.contains)
print(result) //prints true in the above case.

Answer 5

In Swift 4:

    let itemsArray = ["Google", "Goodbye", "Go", "Hello"]
    let searchString = "Go"
    let filterArray = itemsArray.filter({ { $0.range(of: searchString, options: .caseInsensitive) != nil}
    })
    print(filterArray)

Answer 6

func filterContentForSearchText(_ searchText: String) {
   filteredString = itemsArray.filter({( item : String) -> Bool in
            return  item.lowercased().contains(searchText.lowercased())
    })
}

Answer 7

MARK:- Swift 5, Swift 4

//MARK:- You will find the array when its filter in "filteredStrings" variable you can check it by count if count > 0 its means you have find the results

let itemsArray = ["Google", "Goodbye", "Go", "Hello"]
let searchToSearch = "go"

let filteredStrings = itemsArray.filter({(item: String) -> Bool in

    let stringMatch = item.lowercased().range(of: searchToSearch.lowercased())
    return stringMatch != nil ? true : false
})
print(filteredStrings)


if (filteredStrings as NSArray).count > 0
{
    //Record found
    //MARK:- You can also print the result and can do any kind of work with them
}
else
{
    //Record Not found
}

Answer 8

Try like this.

Swift 3.0

import UIKit

let itemsArray = ["Google", "Goodbye", "Go", "Hello"]

var filterdItemsArray = [String]()


func filterContentForSearchText(searchText: String) {
    filterdItemsArray = itemsArray.filter { item in
        return item.lowercased().contains(searchText.lowercased())
    }
}

filterContentForSearchText(searchText: "Go")
print(filterdItemsArray)

Output

["Google", "Goodbye", "Go"]

Answer 9

Swift 5

let itemExist = itemsArray.contains {
    $0.range(of: stringToSearch) != nil
}