check if samba directory exist in python3

Question

I have a samba directory smb://172.16.0.10/public_pictures/ and I would like to know if it is accessible.

try something like the following:

import urllib

if open("smb://172.16.0.10/public_pictures/"):
    print("accessible")
else:
    print("no accessible")

but obviously it does not work for me

Answer 1

Using pysmb (docs):

from smb.SMBConnection import SMBConnection

remote_address = "172.16.0.10"
share_name = "public_pictures"

conn = SMBConnection(username, password, name, remote_name)
conn.connect(remote_address)

accessible = share_name in conn.listShares()

Answer 2

One way of handling samba is to use pysmb. If so, then it goes something like the following:

# we need to provide localhost name to samba
hostname = socket.gethostname()
local_host = (hostname.split('.')[0] if hostname 
              else "SMB{:d}".format(os.getpid()))

# make a connection
cn = SMBConnection(
    <username>, <password>, local_host, <netbios_server_name>,
    domain=<domain>, use_ntlm_v2=<use_ntlm_v2>, 
    is_direct_tcp=<self.is_direct_tcp>)

# connect
if not cn.connect(<remote_host>, <remote_port>):
    raise IOError

# working connection ... to check if a directory exists, ask for its attrs
attrs = cn.getAttributes(<shared_folder_name>, <path>, timeout=30)

Some notes:

• in your example above, public_pictures is the shared folder, while path would be simply /

• you'll need to know if you are using SMB on port 139 or 445 (or a custom port). If the latter you will usually want to pass is_direct_tcp=True (although some servers will still serve NetBIOS samba on 445)

• if you expect not to need a username or password, then probably you are expecting to connect as username="guest" with an empty password.