Convert /bin/bash command to /bin/sh command

Question

I have the following command...

/bin/bash -c 'diff <(sort text2) <(sort text1)'

It sorts each file and pipes them into the diff function. This works well if /bin/bash exists. However, the system I'm on only has /bin/sh. I'm struggling to find the equivalent command for this.

If I run...

/bin/sh -c 'diff <(sort text2) <(sort text1)'

I will get...

/bin/sh: syntax error: unexpected "("

Answer 1

The POSIX shell equivalent of Bash:

bash -c 'diff <(sort text2) <(sort text1)'

is:

sh -c 'trap "rm -fr -- \"$t\"" EXIT ABRT INT;t=$(mktemp -d);mkfifo "$t/a" "$t/b";sort text1>"$t/a"&sort text2>"$t/b"&diff "$t/b" "$t/a"'

Or in a civilized way

#!/usr/bin/env sh

trap 'rm -fr -- "$tmpdir"' EXIT ABRT INT
tmpdir=$(mktemp -d)

FIFO_A="$tmpdir/fifoA"
FIFO_B="$tmpdir/fifoB"
mkfifo -- "$FIFO_A" "$FIFO_B"
sort text1 > "$FIFO_A" &
sort text2 > "$FIFO_B" &
diff -- "$FIFO_B" "$FIFO_A"

Answer 2

Maybe just simple temp files?

sort text1 >a; sort text2 >b; diff b a; rm a b;