Convert rows of beautiful table to list

Question

I would like to convert the rows of beautifultable to elements of a list while excluding the header e.g:

 [['A',2,4], ['B',2,5], ['C',2,1]]

Answer 1

Just call

list(map(list, table))

the full code:

from beautifultable import BeautifulTable
table = BeautifulTable()
table.column_headers = ["c1", "c2", "c3"]
table.append_row(['A', 2, 4])
table.append_row(['B', 2, 5])
table.append_row(['C', 2, 6])
print(table)
# it will print
# +----+----+----+
# | c1 | c2 | c3 |
# +----+----+----+
# | A  | 2  | 4  |
# +----+----+----+
# | B  | 2  | 5  |
# +----+----+----+
# | C  | 2  | 6  |
# +----+----+----+
li = list(map(list, table))
print(li)
# it will print
# [['A', 2, 4], ['B', 2, 5], ['C', 2, 6]]

Answer 2

Beautifultable would give the following result if you try to get the rows:

    list([r for r in table])

 => [RowData<'A',2,4>, RowData<'B',2,5>, RowData<'C',2,1>]  

To convert it to the form: [['A',2,4], ['B',2,5], ['C',2,1]]

Use:

list([list(r) for r in table])