COS ZF Command return Service

Question

In COS I would like to return all the service with a specific name. In command running the command sc queryex type= service state= all | find /i "BFE" and it will display the service name. In COS there is $ZF that can take in a command but it return 0 not sure what i am doing incorrect.

USER>s cmd = "sc queryex type= service state= all | find /i ""BFE"""

USER>W cmd
sc queryex type= service state= all | find /i "BFE"
USER>set rc=$zf(-2,cmd)

USER>W rc
0

Answer 1

I would also add that the $ZF(-1) and $ZF(-2) function is deprecated in the latest version. In the meantime, you can simply append >> resultfile.txt to arg and then review the file. I would however use $ZF(-1) rather than $ZF(-2), which runs the command as a child-process, asynchronously.

Answer 2

in Caché we can call external command with the function $zf, where the first argument could be -1 or -2. Where $zf(-1) waits, while command will be finished, as a result, will be exit code from this command. $zf(-2) does not wait and as a result return 0 if the spawned process was successfully created, and -1 if not. In your case, you should use $zf(-1) because you expecting to get some result immediately. But you have to redirect any output to some temporary file and read it after the call.