I have an array
arr = [1,2,3,4,5]
and I'm wondering if there is a way to cycle through it so something like:
i = 2 arr[3+n]
would return 1, rather than nil
1
nil
Is that possible using the index, or even with next?
next
Perform a modulo on the index using the array size:
arr = [1, 2, 3, 4, 5] arr[5 % arr.size] #=> 1
It's called cycle:
c = [1,2,3,4,5].cycle 10.times{p c.next}
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Perform a modulo on the index using the array size: