I want to get a Double
with 3 decimalplaces. I do this:
String sAveragePrice;
Double dAveragePrice = holePrice/(allPrices.size()); // delivers 1.3210004
DecimalFormat threeZeroes = new DecimalFormat("#0.000");
sAveragePrice = threeZeroes.format(dAveragePrice); // delivers then 1,321
After formatting I dont get a 1.321 but 1,321. And the 1,321 throws a NumberformatException
later. This is when it is thrown:
Double priceInt = Double.parseDouble(sAveragePrice); // throws NumberFormatException
The strange thing is, I have this code till 3 weeks and it didn't make any problem. But today when I have started my app again it gets problem with it. But I didn't have changed anything.
Can anybody help me? I also tried this:
NumberFormat format = NumberFormat.getNumberInstance();
format.setMinimumFractionDigits(3);
format.setMaximumFractionDigits(3);
sAveragePrice = format.format(dAveragePrice);
But it also delivers me a "," instead of a "." for double.
Use this type of formatting use # instead of 0. It is the correct format to declare your pattern
Hope it will help you