Determine the caller of the page which has common page as composition

Question

Assume I'm in page: I clicked on "Create book" link, takes me to Book Creator page and when I click on start Book creator, it returns me Main page

Assume I'm in some search result page: I clicked on "Create book" link, takes me to Book Creator page and when I click on start Book creator, it returns me search result page

you can test this scenario in link Wikipedia page

Same in code:

public class CommonItem {
    Class<?> Calle
    CommonItem(Class<?> Calle) { 
       this.calle = calle;
    }

    public PageX clickLink() {
       return new PageX(Class<?> Calle);
    }

}



public class PageA {
    // WebDriver driver;
    CommonItem ci;

    PageA() {
        ci = new CommonItem(PageA.class);
    }

    public PageX commonItemClick() {
        PageX axp = ci.clickLink();
        return axp;
    }
}


public class PageB {
    CommonItem ci;

    PageB() {
        ci = new CommonItem(PageB.class);
    } 

    public PageX commonItemClick() {
        PageX bxp = ci.clickLink();
        return bxp;
    }
} 


    public class PageX {
      Class<?> calle;
      PageX(Class<?> calle){
            this.calle = calle;
      }
    public void someLink() {
        // Click some Link here
        // return pageA or PageB (depends on which page called this method,  How to determine? )                  
       return calle;
   }
}

Update-1: I've implemented suggestion above. Now I've a test method which calls pageX.someLink() method, returns PageA or PageB,syntax would be

PageX xp = pageA.commonItemClick();
Class<?> caller = xp.someLink();
// how to access method of page A via caller variable ?

Answer 1

From web point of view you may try executing script "window.history.go(-1)" on click of any link or button.

Regarding the java code, the class CommonItem can have a constructor that takes a parameter as to who created it, which can later be used to determine the back-page.