How can I divide 16 8-bit integers by 4 (or shift them 2 to the right) using SSE intrinsics?
Divide 8-bit integers by 4 (or shift) using SSE
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Unfortunately there are no SSE shift instructions for 8 bit elements. If the elements are 8 bit unsigned then you can use a 16 bit shift and mask out the unwanted high bits, e.g.
For 8 bit signed elements it's a little fiddlier, but still possible, although it might just be easier to unpack to 16 bits, do the shifts, then pack back to 8 bits.