Django - Creating a Custom Template Tag to show Model Name

Question

I have a model:

class Survey(models.Model):
name = models.CharField(max_length = 200)

def __str__(self):
    return self.name

And in my template I want to show the name of the current Survey model:

<h1> {{survey.name |name}} </h1>

I'm using a custom template tag/filter to display that name; however, it is showing as 'str' instead of the name of the current Survey model.

Here is the filter code:

from django import template

register = template.Library()

@register.filter
def name(value):
return value.__class__.__name__

What am I doing wrong here?

Answer 1

When you are calling the template tag with <h1> {{survey.name |name}} </h1> you are passing it the string associated with the model. As the field is a CharField it will return a string and therefore the name of the that class is str.

I believe what you are wanting it <h1> {{survey|name}} </h1> which will send the template tag the instance of Survey and therefore get the class name from that.

Answer 2

As an addition to the above answer...

Your filter is calling __class__.__name__, which I believe would return str

Try changing your filter to return value.__name__

See this similar question

Answer 3

you can do something like this:

• if you have defined verbose_name in meta then you can do:

  return (model-name)._meta.verbose_name

• otherwise you can do:

  return (model-name).name