I'm trying to understand how to access multiple input arguments from docopt.Parse() output.
Example:
package main
import (
"fmt"
"github.com/docopt/docopt-go"
)
func main() {
usage := `blah.go
Usage:
blah.go read <file> ...
blah.go -h | --help | --version`
arguments, _ := docopt.Parse(usage, nil, true, "blah 1.0", false)
x := arguments["<file>"]
fmt.Println(x)
fmt.Println(x)
}
Command Line:
$ go run blah.go read file1 file2
[file1 file2]
[file1 file2]
I'd like to print out only file1 or file2.
When I try adding:
fmt.Println(x[0])
I get the following error:
$ go run blah.go read file1 file2
# command-line-arguments
./blah.go:19: invalid operation: x[0] (index of type interface {})
According to the documentation (https://godoc.org/github.com/docopt/docopt.go#Parse) the return type is
map[string]interface{}
which meansarguments["<file>"]
gives you a variable of typeinterface{}
. This means you'll need a type conversion of some sort to use it (http://golang.org/doc/effective_go.html#interface_conversions). Probablyx.([]string)
will do the trick.