Dynamically create password fields in Oracle APEX 19.2

Question

How is it possible to dynamically create password type input fields in Oracle APEX 19.2? Read about using APEX_ITEM package, but there is no function for password fields there.

Answer 1

I just had this problem as well and I had to come up with my own solution, here it is:

First, create your APEX_ITEM with a special class name (I have used 'pwd') In the following example I'll imagine we are creating the Item inside a report:

SELECT APEX_ITEM.TEXT( 1, field_value, NULL, NULL, 'class="pwd"' ) AS pwd_column_name FROM DUAL

After the field has been created run javascript to find the inputs with class 'pwd' and change their type to 'password'. (e.g. on the report add a Dynamic Action -> After Refresh -> Execute Javascript code)

$('.pwd').attr('type', 'password');