encoding in Swift 3

Question

I have the following code which I'm trying to put into Swift 3. The line super.encodeWithCoder(aCoder) is giving problems. Whatever I do gives an error.

import Foundation
class ToDo: Task {
var done: Bool

@objc required init(coder aDecoder: NSCoder) {
    self.done = aDecoder.decodeObjectForKey("done") as! Bool
    super.init(coder: aDecoder)
}

@objc override func encodeWithCoder(aCoder: NSCoder) {
    aCoder.encodeObject(done, forKey: "done")
    super.encodeWithCoder(aCoder)
}

init(name: String, done: Bool) {
    self.done = done
    super.init(name: name)
}
}

I'm trying to convert to Swift 3

I have this

import Foundation

class ToDo: Task {
var done: Bool

@objc required init(coder aDecoder: NSCoder) {
    self.done = aDecoder.decodeObject(forKey: "done") as! Bool
    super.init(coder: aDecoder)
}

@objc override func encode(with aCoder: NSCoder) {
    aCoder.encode(done, forKey: "done")
    // THis line gives an error
    super.encode(with aCoder)

}

init(name: String, done: Bool) {
    self.done = done
    super.init(name: name)
}

}

The line super.encodeWithCoder(aCoder) gives an error . Swift gives no prompt and a search has given no answers.

Edit in response to comments The original code "super.encodeWithCoder(aCoder)" gives the error Value of type 'Task' has no member 'encodeWithCoder'

super.encode(with aCoder) gives error Expected ';' separator

Answer 1

I think the reason that the app crashes is that you use a decodeObject() function for a Bool.

Changing the code to the correct functions yields:

@objc required init(coder aDecoder: NSCoder) {
    super.init(coder: aDecoder)
    self.done = aDecoder.decodeBool(forKey: "done")
}

@objc override func encode(with aCoder: NSCoder) {
 aCoder.encode(done, forKey: "done")
}