I am trying to identify table types based on the columns they contain in a stored procedure. The query I initially came up with is as follows:
SELECT CASE WHEN col_one. IS NOT NULL THEN 'COL1'
WHEN col_two IS NOT NULL THEN 'COL2'
ELSE 'NEITHER'
END
INTO ls_table_type
FROM (SELECT column_name col_one
FROM sys.all_tab_cols
WHERE upper ( owner ) = upper ( '|OWNER|' )
AND hidden_column = 'NO'
AND virtual_column = 'NO'
AND column_id IS NOT NULL
AND column_name = '|COL1_NAME|'
AND table_name = upper(|TABLE_NAME|))
,(SELECT column_name as col_two
FROM sys.all_tab_cols
WHERE upper ( owner ) = upper ( '|OWNER|' )
AND hidden_column = 'NO'
AND virtual_column = 'NO'
AND column_id IS NOT NULL
AND column_name = '|COL2_NAME|'
AND table_name = upper(|TABLE_NAME|))
This does not work unless both columns are present in a table. I am sure I am missing some obvious way of attacking this.
This query should give you the information you need. If col1 and col2 don't exist in the same table then you won't get any duplicate records.