Following code outputs the values in time format, i.e. if it's 1:50pm and 8 seconds, it would output it as 01:50:08
cout << "time remaining: %02d::%02d::%02" << hr << mins << secs;
But what I want to do is (a) convert these ints to char/string (b) and then add the same time format to its corresponding char/string value.
I have already achieved (a), I just want to achieve (b).
e.g.
char currenthour[10] = { 0 }, currentmins[10] = { 0 }, currentsecs[10] = { 0 };
itoa(hr, currenthour, 10);
itoa(mins, currentmins, 10);
itoa(secs, currentsecs, 10);
Now if I output 'currenthour', 'currentmins' and 'currentsecs', it will output the same example time as, 1:50:8, instead of 01:50:08.
Ideas?
If you don't mind the overhead you can use a
std::stringstream