Is this the right Make file code if I want to deploy my Golang server on Amazon AWS EC2 with this configuration:
Im not allowed to embed image so click here to see the image
Here is the Make File Code:
Shipping package
Assumes user is on MacOS, if other OS, please change PROTO_ROOT_DIR to the path of protobuf installation PROTO_ROOT_DIR = $(shell brew
--prefix)/Cellar/protobuf/3.6.0/include PROJECT_NAME = hello-grpc
Dart requires you to manually ship all google provided proto files too.
_gendart: @mkdir -p model/gen/ship/dart @protoc -I=model/protodefs --dart_out=grpc:model/gen/ship/dart model/protodefs/.proto @protoc -I$(PROTO_ROOT_DIR) --dart_out=model/gen/ship/dart $(PROTO_ROOT_DIR)/google/protobuf/.proto
_gengo: @mkdir -p model/gen @protoc -I=model/protodefs --go_out=plugins=grpc:model/gen model/protodefs/*.proto
gen: _gengo _gendart
build: get gen @env CGO_ENABLED=0 GOOS=linux GOARCH=386 go build -ldflags '-w -extldflags "-static"' -o build/${PROJECT_NAME}_linux_amd64 . @env GOARCH=amd64 go build -ldflags '-w -extldflags "-static"' -o build/${PROJECT_NAME}_macosx_amd64 .
get: @go get -u github.com/golang/dep/cmd/dep @dep ensure
install: get gen @cp config_template.json config.json
My confusion is that for building files for Amazon AWS EC2 with the above configuration I need to use (assuming my server go file name is main):
GOOS=linux GOARCH=amd64 go build -o main
But in the Make file this "GOARCH=386" is mentioned in this line:
build: get gen @env CGO_ENABLED=0 GOOS=linux GOARCH=386 go build
What could be the right make file code when Im building Go gRPC Server on Mac OS for the above mentioned Amazon AWS EC2 instance
Please help me :(