Get all occurrences of a string within a directory(including subdirectories) in .gz file using bash?

Question

I want to find all the occurrences of "getId" inside a directory which has subdirectories as follows:

*/*/*/*/*/*/myfile.gz

i tried thisfind -name *myfile.gz -print0 | xargs -0 zgrep -i "getId" but it didn't work. Can anyone tell me the best and simplest approach to get this?

Answer 1

Use the following find approach:

find . -name *myfile.gz -exec zgrep -ai 'getSORByID' {} \;

This will print all possible lines containing getSORByID substring

Answer 2

find ./ -name '*gz' -exec zgrep -aiH 'getSorById' {} \;

find allows you to execute a command on the file using "-exe" and it replaces "{}" with the file name, you terminate the command with "\;"

I added "-H" to zgrep so it also prints out the file path when it has a match, as its helpful. "-a" treats binary files as text (since you might get tar-ed gzipped files)

Lastly, its best to quote your strings in case bash starts globbing them.

https://linux.die.net/man/1/grep https://linux.die.net/man/1/find