this is my xml
<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:end="http://endpoint.ggg.com/">
<soapenv:Header/>
<soapenv:Body>
<end:onlineExpressRemit>
<channelCode>NBPS</channelCode>
</end:onlineExpressRemit>
</soapenv:Body>
</soapenv:Envelope>
and this is my xslt
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:end="http://endpoint.ggg.com/" >
<xsl:template match="/">
<xsl:value-of name="ggg2" select="/soapenv:Envelope/soapenv:Body/*[namespace-uri()]"/>
</xsl:template>
</xsl:stylesheet>
my expected output is display only
onlineExpressRemit
i am very new for xslt, i try name(), local-name() alot others method, however no luck, i cant retrieve only node-name, any help will do, thank you!
You can try using
local-name(soapenv:Envelope/soapenv:Body/*)
, for example, the following XSL transformation :when applied to your XML sample, yield the following output :
Note: I added
<root>
element just because in online XSLT processor I used for testing, there was error when root element is absent. Usually, setting<xsl:output>
is enough to be able to output a non-XML result : XSLT: Transforming into non-xml content?