I have this function
, which plays Spotify
:
#a function to play Spotify
def play(id_):
print 'playing', id_
os.system("osascript -e 'tell application \"Spotify\" to play track \"%s\"'" % (id_,))
and the following loop
, which iterates through all playlist
songs, obtains all playable id
's (foreign_id
), passing them to play(id_)
,
and passes each song duration
to time.sleep()
to halt the loop until each song finishes, repeating the loop all over again:
for i, song in enumerate(song_playlist):
#we need to track each song id
song_id = song_playlist[i]['id']
#in order to get song 'duration', access 'song/profile response' and pass the id as an argument
response_profile = en.get('song/profile', id=song_id, bucket="audio_summary")
song_profile = response_profile['songs']
dur = song_profile[0]['audio_summary']['duration']
#convert to miliseconds
dur *= 1000
print int(round(dur))
#now we access each song 'foreign_id'
for track in song:
track = song['tracks'][i]
track_id = track['foreign_id'].replace('-WW', '')
print '{0} {2} {1}'.format(i, song['artist_name'], song['title'])
#call the function for each track
play(track_id) #CALL FUNCTION HERE
time.sleep(int(round(dur))) # SET INTERVAL CALL TO EACH SONG DURATION
however, only one song plays, and recursion dies out.
how can I correct the code so I can have the function playing all tracks in sequence running the code only once?
It looks like
play(track_id)
should be inside thefor track in song
loop. You need to indent it 1 level.