how can I transform Perl's $1 special variable to Python?

Question

I want to transform a hash that contains hashes in perl to python. here is a piece of its perl code:

our %types = (
  string => {
    db_type     => 'string',
    hint        => 'string',
    pattern     => qr|^(.+)$|,
    format      => q( $1 )
  },
  boolean => {
    db_type     => 'boolean',
    hint        => 'yes|no',
    pattern     => qr|^([yn])|i,
    check       => q( $1 ),
    format      => q( ($1 =~ /^y/) ? 'yes' : 'no' )
  }
)

here is how I wrote it in Python:

types = [
    'string': {
        'db_type': 'string',
        'hint': 'string',
        'pattern': re.compile(r'^(.+)$'),
        # 'format':,
    },
    'boolean': {
        'db_type': 'boolean',
        'hint': 'yes|no',
        'pattern': re.compile(r'^([yn])', re.IGNORECASE),
        #'check': HOW SHOULD I TRANSFORM THIS PART?,
        #'format': HOW SHOULD I TRANSFORM THIS PART?,
    },
]

I don't know how should I transform the values of format and check keys. any help is apperciated.

Answer 1

The $1 is the portion of text that exists in the first parentheses of the evaluated regular expression.

You need to rewrite the whole mechanism, but something like .group(1) for $1 and also

"yes" if object.group(1) == "y" else "no" 

for

($1 =~ /^y/) ? 'yes' : 'no'

should do the job.