How can I use BaseHTTPRequestHandler to forward(routing) the client's Get request to a local server file like Apache?

Question

Let's say there is a path "D:/test.zip", and I have successfully built a server based on BaseHTTPServer( the server is listening on http://127.0.0.1:6000). Its handler class is like this:

class MyBaseHttpHandler(http.server.BaseHTTPRequestHandler):
    def do_GET(self):
        if self.path=="/test.zip":
            print("fetching test.zip.....")
            .....

And now, if I type the url "http://127.0.0.1:6000/test.zip" on my browser, my browser should begin to download this zip file—— just like Apache, where I can designate a directory, and users can then access the directory by entering the "http://host:port/directory".

(I don't know how to override the do_GET method to redirect the request to make the file accessible by the client).

By the way, I don't want to create a html file to do this, and I also don't want to use SimpleHTTPServer or Flask, Django to do that, though they may do it well.

Answer 1

Have you tried:

class MyBaseHttpHandler(http.server.BaseHTTPRequestHandler):
    def do_GET(self):
        if self.path == "/test.zip":
            self.send_response(200)
            self.send_header('Content-type', 'application/zip')
            self.end_headers()
            with open("D:\\test.zip", 'rb') as f:
                self.wfile.write(f.read())