How do I create an ordered list of [T, Int] in descending order for any orderable T?

Question

I looked at this page to see how to create a list of map items in descending order of the count those items occur in an original list. I have to do this for a bunch of lists of different types: String, Int, Short, Float, Byte, ...

I could write:

def freqA(a: List[String]): ListMap[String, Int] =
  ListMap(a.groupBy(i => i).mapValues(_.size).toSeq.sortWith(_._2 > _._2):_*)

def freqB(a: List[Int]): ListMap[Int, Int] =
  ListMap(a.groupBy(i => i).mapValues(_.size).toSeq.sortWith(_._2 > _._2):_*)

...

but I just want to write this once using a type T. I thought I remembered how to do this, but I'm blanking out. I hope this is easy for someone.

Answer 1

Never mind, I figured it out. Thank you Scala for not making it too hard on a Friday afternoon:

def freqB[T](a: List[T]): ListMap[T, Int] =
    ListMap[T, Int](a.groupBy(i => i).mapValues(_.size).toSeq.sortWith(_._2 > _._2):_*)