How do I get access to filehandle and format respectively by typeglob?

Question

It seems filehandle and format doesn't have any prefix,so I can't get reference to them by tricks like %{*spud}.

Is there anything I'm missing?

UPDATE

How do I access the format? Why do $fd=*STDOUT and $fd=\*STDOUT both work?

UPDATE2

Code:

package Foo;
our $spud = 'a scalar';
our @spud = 'an array';
our %spud = (a => 'hash');
sub spud {}
format spud =
.
open 'spud', $0; 

my $stash = \%Foo::;
my $name  = 'spud';
my $glob  = $$stash{$name};

for my $type (qw(SCALAR ARRAY HASH CODE IO FORMAT)) {
    #this works
    #print *$glob{$type}, $/; 
    #this doesn't work,only output one row of scalar                                  
    print *{$FOO::{spud}}{$type}, $/; 
}

Output:

[root@perl]# perl tb
SCALAR(0xa4dcf30)





[root@perl]# 

Answer 1

{package Foo;
    our $spud = 'a scalar';
    our @spud = 'an array';
    our %spud = (a => 'hash');
    sub spud {}
    format spud =
.
    open 'spud', $0;
}

my $stash = \%Foo::;
my $name  = 'spud';
my $glob  = $$stash{$name};

for my $type (qw(SCALAR ARRAY HASH CODE IO FORMAT)) {
     print *$glob{$type}, $/;
}

prints:

SCALAR(0x810070)
ARRAY(0x81c750)
HASH(0x81bb00)
CODE(0x81bbd0)
IO::Handle=IO(0x81b670)
FORMAT(0x81bc40)

Answer 2

*spud will give you the filehandle from the type glob. See here: Typeglobs and Filehandles