I'm reading about scheduling, but I can't figure out how a scheduler regains control after it invokes code in the user space.
E.g. the scheduler passes the control to some app in the user space which does some infinite loop and no other hardware interrupt occurs on an one core chip. All documents talk about the scheduler regaining control and preemptivly interrupting the user process, but how does that work if the control is never passed back to the OS?
Question: Does the scheduler register with some clock in the CPU to be given control again after X msecs? Or is there some other trick? If no, what is the C function called to register for regular (or one time?) control regains?
If no other interrupt occured, a preemptive O/S wouldn't despatch, and the user application would loop for ever.
This won't happen, though. Typically, a preemptive scheduler will despatch on every system call, every interrupt, and every tick of the system clock. The system clock will always interrupt, so your infinite loop simply won't occur.
The Pick operating system (after its developer Dick Pick) used a non-preemptive scheduler. Software developed for this system was required to make a system call periodically to allow the kernel to despatch other processes. In this environment the kernel would otherwise lose control completely until the process terminated.
The argument used in its justification was that considerable time was spent saving and restoring the processor state during a despatch. Forcing the application to take responsibility for this would allow a faster despatch process.