How to call a type hinted php function without parameter

Question

I have a php function:

function myFunc(MyClass inst) {
    // ...
}

Sometimes, when I call this function, I dont want to pass any arguments, but this doesn't work:

myFunc(null);

The error message is:

... must be an instance of MyClass , null given

Answer 1

Make your function's arguments optional, by providing default values. So instead of

function myFunc(MyClass inst)

it should be

function myFunc(MyClass inst=null)

See docs http://php.net/manual/en/functions.arguments.php

Answer 2

Just put the default initializer like so:

function myFunc(MyClass inst=null) {
    // ...
}

Then if you don't want to pass params, call it without ones :D