Lets take an example you have two employee object having same values as follows.
Employee employee1 = new Employee(1001, "Sam", 20000);
Employee employee2 = new Employee(1001, "Sam", 20000);
if(doCompareEmployees(employee1, employee2)){
System.out.println("Both employee objects are same.");
}else{
System.out.println("Both employee objects are not same.");
}
//Here is compare method using java 8.
private boolean doCompareEmployees(Employee employee1, Employee employee2) {
int returnValue = Comparator.comparing(Employee::getID)
.thenComparing(Employee::getName)
.thenComparing(Employee::getSalary)
.compare(employee1, employee2);
if (returnValue != 0){
return false;
}
return true;
}
I would like know about, is there any other better approach to compare objects in Java 8 ?
If you do not want to define an ordering on your objects, normally you would not write a Comparator.
The typical way to define equality for a class, is to define both an
equals()
and ahashCode()
method. To implementhashCode()
,Objects.hash()
can help (present since Java 7).Although lambda expressions allow to write very elegant code in some cases, they are not the best solution for each problem.