How to convert a file name from decimal to heximal?

Question

From this website and on the internet I have looked for this answer, but could not find it specific. My knowledge of Linux is not so big, but here is my problem: I would like to convert a JPG file with a 8 characters file name. So from 2014-12-12 23.59.59.jpg to 484140b7.jpg (heximal). I came up or found this code:

ddate=$(exiv2 "${i}"|grep timestamp|cut -c 24-37|tr -d " :")
cp "$i" "${ddate}.jpg"

I saw here and there you can use something like printf "%x\n", but I don't manage to get it to work.

Can somebody help me with this?

Thank you already very much!

Answer 1

Maybe something like this:

for x in *.jpg; do
    f=$(sed "s/[^0-9]//g" <<< "$x")
    cp "$x" "$(printf "%x.jpg" "$f")"
done

If you want to remove the year from the front of the date first, you could use a cut as you attempted:

for x in *.jpg; do
    f=$(sed -e "s/[^0-9]//g" -e "s/^....//" <<< "$x")
    cp "$x" "$(printf "%x.jpg" "$f")"
done