How to convert a generic xml format block to properties format String from an xml file using ksh script

Question

With the conditions:

1. I cannot use any XML parser tool as I don't have permission , read only

2. My xmllint version does not support xpath, and I cannot update it , read only

3. I dont have xmlstarlet and cannot install it

My options are limited to almost String processing.

An input parameter will be provided by the user and it will be the name of the block.

So,

let's assume

NAME=${USER_INPUT}

and we will use $NAME as the parameter to search the xml block that will be searched.

How can I convert a generic xml block like this in an xml file like this:

<block>
 <name>Bob</name>
 <address>USA</address>
 <email>[email protected]</email>
 <phone>1234567</phone>
</block>

<block>
 <name>Peter</name>
 <food>France</address>
 <cell>[email protected]</cell>
 <drinks>Coke</drinks>
 <car>Honda</car>
 <bike>Mountain bike</bike>
</block>

So the thing that I want to achieve here is to get the xml block that satisfies my search ,

for example NAME=Bob ;

The output of the script should be in properties file format

name=Bob
address=USA
[email protected]
phone=1234567

A thing to consider here is that the xml format per block are different. The nodes are not the same for every xml block.

Answer 1

With bash and GNU sed:

#!/bin/bash

NAME="Bob"
sed -n '/name>'${NAME}'/,/<\/block>/s/.*<\(.*\)>\(.*\)<.*/\1=\2/p' file.xml

Output:

name=Bob
address=USA
[email protected]
phone=1234567