How to fallthrough to a specific case in switch statement

Question

In my first section I show different style UIAlertController based on the row. Second section does unrelated stuff. In order to avoid code duplication in both cases, how do I fallthrough to a specific case in switch statement? Is this possible in swift? Does any other language have this concept?

override func tableView(tableView: UITableView, didSelectRowAtIndexPath indexPath: NSIndexPath) {
    tableView.deselectRowAtIndexPath(indexPath, animated: true)
    var alertController: UIAlertController!
    let cancelAction = UIAlertAction(title: L10n.Cancel.localized, style: .Cancel) { (action) in
        // ...
    }
    switch (indexPath.section, indexPath.row) {
    case (0, 0):
        alertController = UIAlertController(title: nil, message: nil, preferredStyle: .ActionSheet)
        //add other actions
    case (0, 1):
        alertController = UIAlertController(title: nil, message: nil, preferredStyle: .Alert)
        //add other actions
    case (0, _): //this case handles indexPath.section == 0 && indexPath.row != 0 or 1
        //I want this to be called too if indexPath.section is 0;
        //even if indexPath.row is 0 or 1.
        alertController.addAction(cancelAction)
        presentViewController(alertController, animated: true, completion: nil)
    default:
        break
    }
}

Answer 1

What you are trying to achieve currently doesn't seem to be possible with Swift switch statements. As mentioned in another answer by @AMomchilov

switch statements in Swift do not fall through the bottom of each case and into the next one by default. Instead, the entire switch statement finishes its execution as soon as the first matching switch case is completed, without requiring an explicit break statement.

The fallthrough keyword also doesn't seem to solve the problem, since it won't evaluate the case conditions:

A fallthrough statement causes program execution to continue from one case in a switch statement to the next case. Program execution continues to the next case even if the patterns of the case label do not match the value of the switch statement’s control expression.

I think that the best solution would be to have something like

switch (indexPath.section, indexPath.row) {
case (0, _):
    if indexPath.row == 0 {
        alertController = UIAlertController(title: nil, message: nil, preferredStyle: .ActionSheet)
    }
    alertController = UIAlertController(title: nil, message: nil, preferredStyle: .Alert)
    alertController.addAction(cancelAction)
    presentViewController(alertController, animated: true, completion: nil)
default:
    break
}

Answer 2

You use the fallthrough keyword.

No Implicit Fallthrough

In contrast with switch statements in C and Objective-C, switch statements in Swift do not fall through the bottom of each case and into the next one by default. Instead, the entire switch statement finishes its execution as soon as the first matching switch case is completed, without requiring an explicit break statement. This makes the switch statement safer and easier to use than the one in C and avoids executing more than one switch case by mistake. -The Swift Programming Language (Swift 2.2) - Control Flow

However, the fallthrough keyword can only be used to add on functionality. You can't have the first and second case be mutually exclusive, and also fallthrough to the third case. In your situation would refactor the common case to occur unconditionally after the switch statement, and change the default case from break to return.