Forgive me if this seems obvious, I am VERY new to R. So I am trying to get random Spike Train that looks like a vector [ 1 0 1 1 0 0 0 1] and for one instance, I have been able to do it using the following code:
fr = 100 #Firing rate of 100Hz
dt = 1/1000 #Short duration of time dt
nBins = 10 #10msSpikeTrain
x = runif(nBins) #Creating a "nBins" length string of random variable
#falling uniformly between 0 and 1
x
y<- numeric(nBins) # creating an empty vector of size nBins
MyPoissonSpikeTrain = function(x){
for (i in 1:nBins){
if (x[i] < fr*dt)
y[i]=1
else
y[i]=0
}
return(y)
}
#Creating a function that that returns its values in vector y as 1 if the
#spike was fired
#and 0 if the spike wasn't fired.
#Spike was fired, if randomly generated x value is smaller than fr*dt.
MyPoissonSpikeTrain(x)
This works all well, but I want to create a matrix where 1st row would be one instance of the above procedure, 2nd row would be 2nd instance and so on.
I want this process happening (say) 20 times, and then put each of the individual y I find as a row of a Bigger Matrix, say Y. I understand that I need to modify my y to be a matrix and not a vector and then modify my MyPoissonSpikeTrain function accordingly to have the output create a matrix but I can't figure out how to do it. Any help will be appreciated.
This function can be simplified a lot, check this out:
now it is vectorized, and you can change the arguments if you wish. Now to generate the desired matrix:
Here each column is one repetition, if you want it the other way round use:
t
If you want to change some argument:
or even better:
so you can pass additional argument to runif