How to move a file in python without knowing the path of the file you want to move? (Half way done)

Question

I am searching for a file and its path in python, I get the result printed with the full path and file I am searching for. How do I set the print result as a variable so I can copy and move it to another folder?

import os

def find_files(filename, search_path):
    result = []

    for root, dir, files in os.walk(search_path):
        if filename in files:
            result.append(os.path.join(root, filename))
    return result 

print(find_files("myfile.exe","C:"))

When I run the .py file, it prints the full path of the file myfile.exe which is great, but how do I set it to get the path inside my function and move it to another folder/path?

I do not want to print the path of the file on the terminal, I want to use that path inside my program so I can use it to move it to another folder.

Thank you very much for your help!

Answer 1

If you extract the single item from result, you get path:

import os

def find_files(filename, search_path):
    result = []

    for root, dir, files in os.walk(search_path):
        if filename in files:
            result.append(os.path.join(root, filename))
    return result[0]

PATH = find_files("test", r"C:\Users\UserName\Desktop")
PATH

Output:

'C:\\Users\\UserName\\Desktop\\test'