I have one situation I have to plot the table horizontally. The Data is dynamic.
Iteam 1
RowHeder1 : Value 1
RowHeder2 : Value 2
RowHeder3 : Value 3
RowHeder4 : Value 4
How can I create it? And is it possible to pass the cell filter along with data object?
$scope.gridOptions.data =[
{
"display": "RowHeder1 ",
"property":23.24,
"CellFilter": "MyFilter | $"
},
{
"display": "RowHeder2 ",
"property":"2nd June",
"CellFilter": "MyDateFilter | DD-MM-YY"
},
]
plunker Here Thanks in Advance :) Kiran Gopal
No that is not possible because
cellFilter
is a property of thecolumnDef
and that cannot be changed.However you can create a method/service where you can "process" your data and then pass it to the grid. Based on your data you can create the
columnDef
with the rightcellFilter
so the grid will work as expected.If this is not clear enough please create a JSFiddle with your data and add a link as a comment.