How to place the output of an echo statement and an arp statement on one line?

Question

How can I get the output "echo" and "macaddress" on one line? This is what I've got:

ipRange="192.168.0."
macaddress= arp  | grep -w  "$ipRange$1" | awk '{print $3,$1}' 

ping -c1 "$ipRange$1" > /dev/null
         if [ $? -eq 0 ]; then
echo  "deze host met mac address en ip address is up $macaddress"
else 
echo "het is down"
fi

This is the output:

VirtualBox ~ $ bash test2.sh 149
e0:b9:a5:f8:24:c3 192.168.0.149
deze host met mac address en ip address is up 

Answer 1

Just replace macaddress= arp | grep -w "$ipRange$1" | awk '{print $3,$1}'

with macaddress=$(arp | grep -w "$ipRange$1" | awk '{print $3,$1}')

Answer 2

this should do output in single line

ipRange="192.168.0."
macaddress=$(arp  | grep -w  "$ipRange$1" | awk '{print $3,$1}')

ping -c1 "$ipRange$1" > /dev/null
         if [ $? -eq 0 ]; then
echo  "deze host met mac address en ip address is up $macaddress"
else 
echo "het is down"
fi