How to send value to filter in if condition django?

Question

In my html, I want to send this values to my filter but I got this error :

ValueError at / invalid literal for int() with base 10: '{{request.user.id}}'

My HTML:

<span><i{% if post|liked:"{{request.user.id}},{{post.id}}" %} class="fa fa-heart pointer" {% else %} class="fa fa-heart-o pointer" {% endif %} aria-hidden="true"></i> <span class="text-dark">{{ post.likes.count }}</span>

My Filter:

@register.filter()
@stringfilter
def liked(value, args):
    values = args.split(',')
    user_id, post_id = values
    user = User.objects.get(id=user_id)
    post = Post.objects.get(id=post_id)
    is_liked = post.likes.get(id=user_id)
   
    if is_liked != None:
        return True
    else:
        return False

Thanks for any answer.

Answer 1

It's just a user.id not request.user.id in the template: So,

<span><i{% if post|liked:"{{user.id}},{{post.id}}" %} class="fa fa-heart pointer" {% else %} class="fa fa-heart-o pointer" {% endif %} aria-hidden="true"></i> <span class="text-dark">{{ post.likes.count }}</span>

EDIT

As filter is not taking variable as variable. So, this could be the way:

{% with args=user.id|add:", "|add:post.id %}
    <span><i{% if post|liked:args %} class="fa fa-heart pointer" {% else %} class="fa fa-heart-o pointer" {% endif %} aria-hidden="true"></i> <span class="text-dark">{{ post.likes.count }}</span>
{% endwith %}

See with