How to use \n new line in VB msgbox() ...?

Question

What is the alternative to \n (for new line) in a MsgBox()?

Answer 1

• for VB: vbCrLf or vbNewLine
• for VB.NET: Environment.NewLine or vbCrLf or Constants.vbCrLf

Info on VB.NET new line: http://msdn.microsoft.com/en-us/library/system.environment.newline.aspx

The info for Environment.NewLine came from Cody Gray and J Vermeire

Answer 2

msgbox("your text here" & Environment.NewLine & "more text") is the easist way. no point in making your code harder or more ocmplicated than you need it to be...

Answer 3

Use the Environment.NewLine property

Answer 4

Add a vbNewLine as:

"text1" & vbNewLine & "text2"

Answer 5

These are the character sequences to create a new line:

• vbCr is the carriage return (return to line beginning),

• vbLf is the line feed (go to next line)

• vbCrLf is the carriage return / line feed (similar to pressing Enter)

I prefer vbNewLine as it is system independent (vbCrLf may not be a true new line on some systems)

Answer 6

Try using vbcrlf for a newline

msgbox "This is how" & vbcrlf & "to get a new line"

Answer 7

This work for me: MessageBox.Show("YourString" & vbcrlf & "YourNewLineString")

Answer 8

You can use Environment.NewLine OR vbCrLF OR vbNewLine

MsgBox($"Hi!{Environment.NewLine}I'M HERE")

Answer 9

An alternative to Environment.NewLine is to use :

Regex.Unescape("\n\tHello World\n")

from System.Text.RegularExpressions

This allows you to escape Text without Concatenating strings as you can in C#, C, java

Answer 10

Module MyHelpers
    <Extension()>
    Public Function UnEscape(ByVal aString As String) As String

       Return Regex.Unescape(aString)

    End Function
End Module

Usage:

console.writeline("Ciao!\n".unEscape)

Answer 11

Use the command "vbNewLine"

Example

Hello & vbNewLine & "World"

will show up as Hello on one line and World on another

Answer 12

You can use carriage return character (Chr(13)), a linefeed character (Chr(10)) also like

MsgBox "Message Name: " & objSymbol1.Name & Chr(13) & "Value of BIT-1: " & (myMessage1.Data(1)) & Chr(13) & "MessageCount: " & ReceiveMessages.Count

Answer 13

The correct format is :

"text1" + vbNewLine + "text2"

Answer 14

do not forget to set the Multiline property to true in textbox

Answer 15

On my side I created a sub MyMsgBox replacing \n in the prompt by ControlChars.NewLine

Answer 16

A lot of the stuff above didn't work for me. What did end up working is

Chr(13)

Answer 17

The message box must end with a text and not with a variable