I'm trying to write a c program for sin x using Taylor series but not being able to figure out my mistake while executing the program

Question

Firstly I have defined pi and a function called fact for finding factorial values. Using Taylor series we have sin(x)= x-(x^3)/3! + (x^5)/5! - ....... upto 10th term. nemo is the abbreviation for numerator and deno for denominator for the following terms. Value stores the value of sin(x).

Here's the code that I have tried writing:

#include<stdio.h>
#include<math.h>

#define pi 3.142

int fact(int);

int main()
{
    int i, j;
    float x, value, nume, deno;
    printf("Enter the value for sin x in degrees: \t");
    scanf("%f", &x);
    x= (pi * x)/100;
    value = 0;
    i=1;
    while(i== 1)
        value = value+ x;
    i = 2;
    for(i=2; i<=10; i++)
    {
        while (i%2 !=0)
        {

            nume = pow(x,i);
            deno = fact(i);
            for(j = 2; j<i; j++)

                if(j%2 == 0)
                value = value - (nume/deno);
            else
                value = value + (nume/deno);

            nume = 0;
            deno = 0;
        }

    }
    printf("value of sin x is : \t");
    printf("%f", value);
    return 0;
}

int fact(int n)
{
    if(n==0)
        return 1;
    else
        return (n*fact(n-1));
}

Not being able to figure out what's going wrong. When I'm executing it only prints Enter the value of sin x in degrees Please help me to fix this code.