Scala - null (?) as default value for named Int parameter

Question

I'd like to do in Scala something I would do in Java like this:

public void recv(String from) {
    recv(from, null);
}
public void recv(String from, Integer key) {
    /* if key defined do some preliminary work */
    /* do real work */
}

// case 1
recv("/x/y/z");
// case 2
recv("/x/y/z", 1);

In Scala I could do:

def recv(from: String,
         key: Int = null.asInstanceOf[Int]) {
    /* ... */
}

but it looks ugly. Or I could do:

def recv(from: String,
         key: Option[Int] = None) {
    /* ... */
}

but now call with key looks ugly:

// case 2
recv("/x/y/z", Some(1));

What's the proper Scala way? Thank you.

Answer 1

The Option way is the Scala way. You can make the user code a little nicer by providing helper methods.

private def recv(from: String, key: Option[Int]) {
  /* ... */
}

def recv(from: String, key: Int) {
  recv(from, Some(key))
}

def recv(from: String) {
  recv(from, None)
}

null.asInstanceOf[Int] evaluates to 0 by the way.

Answer 2

The proper way is, of course, to use Option. If you have problems with how it looks, you can always resort to what you did in Java: use java.lang.Integer.

Answer 3

Option really does sound like the right solution to your problem - you really do want to have an "optional" Int.

If you're worried about callers having to use Some, why not:

def recv(from: String) {
  recv(from, None)
}

def recv(from: String, key: Int) {
  recv(from, Some(key))
}

def recv(from: String, key: Option[Int]) {
  ...
}