Javascript: calculate number of days in month for a given year

Question

I have a HTML page with 3 dropdowns for the month, day and year and I was wondering if there was a way to populate the month drop down properly depending on the month and year.

I haven't done this before on the client side, but it looks like a lot of controls like the jQuery DatePicker are doing that behind the scenes.

Answer 1

You can play with date objects:

var monthStart = new Date(year, month, 1);
var monthEnd = new Date(year, month + 1, 1);
var monthLength = (monthEnd - monthStart) / (1000 * 60 * 60 * 24)

Arithmetic with Date objects gives a number of milliseconds.

This will even work for December; the Date constructor handles out-of-range arguments by wrapping around.

Note that month is zero-based (it must be between 0 and 11)

Answer 2

As far as I know, there's no (neat) built-in function for that. I wrote this once:

// note that month is 0-based, like in the Date object. Adjust if necessary.
function getNumberOfDays(year, month) {
    var isLeap = ((year % 4) == 0 && ((year % 100) != 0 || (year % 400) == 0));
    return [31, (isLeap ? 29 : 28), 31, 30, 31, 30, 31, 31, 30, 31, 30, 31][month];
}

Answer 3

Date.prototype.daysinMonth: function(){
    var d= new Date(this.getFullYear(), this.getMonth()+1, 0);
    return d.getDate();
}

function daysinMonthfromInput(month,year){
    return (new Date(year,month-1,1)).daysinMonth();
}

alert(daysinMonthfromInput(2,2011));

Answer 4

Here's the one liner. Assuming you are saying January=1, February=2 etc..(being normal) Here's the leap year example:

var y = 2012;
var m = 2;
var daysInMonth = new Date(y,m,1,-1).getDate();

Answer 5

I am using this approach in my current project and found that I needed correct for round off errors. So instead of using monthLength in my code, I had to use this instead:

monthLength.toFixed(0)

For example if I have an object in which I am storing a text date field, it may look like this:

obj.month = theMonths[mm - 1] + " " + monthLength.toFixed(0) + ", " + obj.year;

Answer 6

Copy from another post: Get number days in a specified month using javascript?

//Month is 1 based
function daysInMonth(month,year) {
return new Date(year, month, 0).getDate();
}

//July
daysInMonth(7,2009); //31
//February
daysInMonth(2,2009); //28
daysInMonth(2,2008); //29

All the credits to @c_harm, really great solution

Answer 7

You can actually use this:

var curdate = new Date(); DaysMonth = 32 - new Date(curdate.getYear(), curdate.getMonth(), 32).getDate();

;)

Answer 8

Date.prototype.daysinMonth= function(){
var d= new Date(this.getFullYear(), this.getMonth()+1, 0);
return d.getDate();
};

function daysinMonthfromInput  (month, year) {
     return (new Date(year, month - 1, 1)).daysinMonth();
};
function fillallday (elem, month, year) {
     var options = null;
     var elementExists = document.getElementById(elem);

     if (elementExists != null) {

         this.removeOptions(elementExists);
         var opt = document.createElement('option');
         opt.value = "";
         opt.innerHTML = "---Day---";
         elementExists.appendChild(opt);
         if (month != "") {
             if (typeof (year) === "undefined") {
                 year = new Date().getFullYear();
             }
             if (year == "") {
                 year = new Date().getFullYear();
             }
             var days = daysinMonthfromInput(month, year);
             for (var i = 1; i <= days; i++) {
                 var opt = document.createElement('option');
                 opt.value = i;
                 opt.innerHTML = i;
                 elementExists.appendChild(opt);
             }
         }
     }

 }

Answer 9

This is a possible improvement to the answer given by @MattiVirkkunen:

If you are interested in squeezing every ounce of efficiency from this calculation you should turn this inside out, handling all 'not February' cases first which avoids leap year calculations when the month is not February (11/12 of the time). You can also code it inline which avoids expensive function linkages.

month!=2 ? [31,28,31,30,31,30,31,31,30,31,30,31][month]
         : (year%4!=0 ? 28 : (year%100!=0 : 29 (year%400!=0 ? 28 : 29)));