long long int bit representation, C++

Question

This is my code:

template <typename T> void printlnbits(T v) {
    
    const int value_size = sizeof(v) * 8;

    long long int* ch = (long long int*)&v;

    int j = 0;

    for (int i = value_size - 1; i >= 0; --i)
    {
        extractBit(*ch, i);

        j++;

        if (j == 8)
        {
            std::cout << " ";
            j = 0;
        }
    }

    std::cout << "\t" << value_size << std::endl;
}

and

void extractBit(long long int ch, int ith) {
    std::cout << (ch & (1 << ith) ? 1 : 0);
}

When passing in the argument: const long long unsigned e = 1LLU << 40; the output is:

10000000 00000000 00000000 00000000 10000000 00000000 00000000 00000000 64

Now 1LLU << 40 = 1099511627776

Should'nt the output be:

00000000 00000000 00000000 10000000 00000000 00000000 00000000 00000000 64

Am I missing something?

Struct as argument:

When I am sending in a struct as argument, how does the calculation of the variables inside the struct get calculated together and store a value which then gets outputed as a bit representation?

struct foo {
    int a = 2;
    char b = -1;
    unsigned long long int x = 1LLU << 63;
};

outputs:

00000000 00000000 00000000 00000000 00000000 00000000 00000000 00000000 11001100 11001100 11001100 11111111 00000000 00000000 00000000 00000010 128